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0=16x^2+4.8x
We move all terms to the left:
0-(16x^2+4.8x)=0
We add all the numbers together, and all the variables
-(16x^2+4.8x)=0
We get rid of parentheses
-16x^2-4.8x=0
a = -16; b = -4.8; c = 0;
Δ = b2-4ac
Δ = -4.82-4·(-16)·0
Δ = 23.04
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4.8)-\sqrt{23.04}}{2*-16}=\frac{4.8-\sqrt{23.04}}{-32} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4.8)+\sqrt{23.04}}{2*-16}=\frac{4.8+\sqrt{23.04}}{-32} $
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